Method arguments in Python [duplicate]

This question already has answers here: What is the purpose of the `self` parameter? Why is it needed? (26 answers) Closed 5 months ago.

Suppose I have this code:

class Num:
    def __init__(self,num):
        self.n = num
    def getn(self):
        return self.n
    def getone():
        return 1
myObj = Num(3)

print(myObj.getn()) # result: 3

But if I try 开发者_运维百科print(myObj.getone()), I get an error: 'getone()' takes no arguments (1 given).

So I replace:

def getone():
    return 1

with

def getone(self):
    return 1

Now print(myObj.getone()) shows 1, as expected. But - getone() doesn't need any arguments in order to just return 1. Do I have to use a meaningless argument?

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In Python:

• Instance methods: require the self argument.
• Class methods: take the class as a first argument.
• Static methods: do not require either the instance (self) or the class (cls) argument.

__init__ is a special function and without overriding __new__ it will always be given the instance of the class as its first argument.

An example using the builtin classmethod and staticmethod decorators:

import sys

class Num:
    max = sys.maxint

    def __init__(self,num):
        self.n = num

    def getn(self):
        return self.n

    @staticmethod
    def getone():
        return 1

    @classmethod
    def getmax(cls):
        return cls.max

myObj = Num(3)
# with the appropriate decorator these should work fine
myObj.getone()
myObj.getmax()
myObj.getn()

That said, I would try to use @classmethod/@staticmethod sparingly. If you find yourself creating objects that consist of nothing but staticmethods the more pythonic thing to do would be to create a new module of related functions.

---

Every method needs to accept one argument: The instance itself (or the class if it is a static method).

Read more about classes in Python.

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The fact that your method does not use the self argument (which is a reference to the instance that the method is attached to) doesn't mean you can leave it out. It always has to be there, because Python is always going to try to pass it in.

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In python you must always pass in at least one argument to class methods, the argument is self and it is not meaningless its a reference to the instance itself

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The current object is explicitly passed to the method as the first parameter. self is the conventional name. You can call it anything you want but it is strongly advised that you stick with this convention to avoid confusion.

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If you print(type(Num.getone)) you will get <class 'function'>.

It is just a plain function, and be called as usual (with no arguments):

Num.getone() # returns 1  as expected

but if you print print(type(myObj.getone)) you will get <class 'method'>.

So when you call getone() from an instance of the class, Python automatically "transforms" the function defined in a class into a method.

An instance method requires the first argument to be the instance object. You can think myObj.getone() as syntactic sugar for

Num.getone(myObj) # this explains the Error 'getone()' takes no arguments (1 given).

For example:

class Num:
    def __init__(self,num):
        self.n = num
    def getid(self):
        return id(self)

myObj=Num(3)

Now if you

print(id(myObj) == myObj.getid())    
# returns True

As you can see self and myObj are the same object