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jQuery - Can the show() function return true?

开发者 https://www.devze.com 2023-02-14 19:58 出处:网络
I have make a script by using jQuery such as : $(document).ready(function() { $(\'a[name=pmRead]\').click(function(e) {

I have make a script by using jQuery such as :

$(document).ready(function() {
    $('a[name=pmRead]').click(function(e) {
        e.preventDefault();

        var pmtext=$(this).parents(".pmMain").find(".pmMain5");
    });         
});

Now, I'd like to use a function 开发者_Python百科like pmtext.show() and get TRUE if the element is visible. Else, I'd like to return FALSE. Any change to get TRUE/FALSE by using show()? (or the sister function hide()).


There is a function to check the visibility, but it is not show()/hide().

if (pmtext.is(':visible')) {
    // ....
}


Why not use the following:

pmtext.is(":visible");

That will provide a boolean true if it is visible and false if it is not. For the converse you can use pmtext.is(":hidden");.

If you want to do something on visible, try:

$(this).parents(".pmMain").find(".pmMain5:visible").hide();  // only finds it if visible


I'd suggest writing a custom function if you need to return true or false.

function customShow(element)
{
    if( $( element ).is( ':visible' ) )
        return true;

    $( element ).show();
    return false;
}


You can write your own simple function, to check if its visible or not.

Note: The function takes a jQuery element as input.

function isVisible($element) {
   return $element.css("display").toLowerCase() != "none");
}


Have you looked at the .toggle() method? It optionally accepts a "showOrHide" argument.


<script language="JavaScript">

function menu(bolum) {

if ( bolum.style.display =='none') { bolum.style.display='';islem.style.display='';} else {bolum.style.display='none';} }

</script>

<img src="images/biz-arayalim.png" onclick="menu(firmamesajkutusu)" style="cursor:pointer;"> <div name="firmamesajkutusu" id="firmamesajkutusu"></div>

Old system javascript all div kontrol function

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