I would like to subclass numpy ndarray. However, I cannot change the array. Why self = ...
does not change the array? Thanks.
import numpy as np
class Data(np.ndarray):
def __new__(cls, inputarr):
obj = np.asarray(inputarr).view(cls)
return obj
def remove_some(self, t):
test_cols, test_vals = zip(*t)
test_cols = self[list(test_cols)]
test_vals = np.array(test_vals, test_cols.dtype)
self = self[test_cols != test_vals] # Is this part correct?
print len(self) # correct result
z = np开发者_运维百科.array([(1,2,3), (4,5,6), (7,8,9)],
dtype=[('a', int), ('b', int), ('c', int)])
d = Data(z)
d.remove_some([('a',4)])
print len(d) # output the same size as original. Why?
The reason you are not getting the result you expect is because you are re-assigning self
within the method remove_some
. You are just creating a new local variable self
. If your array shape were not to change, you could simply do self[:] = ... and you could keep the reference to self
and all would be well, but you are trying to change the shape of self
. Which means we need to re-allocate some new memory and change where we point when we refer to self
.
I don't know how to do this. I thought it could be achieved by __array_finalize__
or __array__
or __array_wrap__
. But everything I've tried is falling short.
Now, there's another way to go about this that doesn't subclass ndarray
. You can make a new class that keeps an attribute that is an ndarray and then override all the usual __add__
, __mul__
, etc.. Something like this:
Class Data(object):
def __init__(self, inarr):
self._array = np.array(inarr)
def remove_some(x):
self._array = self._array[x]
def __add__(self, other):
return np.add(self._array, other)
Well, you get the picture. It's a pain to override all the operators, but in the long run, I think more flexible.
You'll have to read this thoroughly to do it right. There are methods like __array_finalize__
that need to be called a the right time to do "cleanup".
Perhaps make this a function, rather than a method:
import numpy as np
def remove_row(arr,col,val):
return arr[arr[col]!=val]
z = np.array([(1,2,3), (4,5,6), (7,8,9)],
dtype=[('a', int), ('b', int), ('c', int)])
z=remove_row(z,'a',4)
print(repr(z))
# array([(1, 2, 3), (7, 8, 9)],
# dtype=[('a', '<i4'), ('b', '<i4'), ('c', '<i4')])
Or, if you want it as a method,
import numpy as np
class Data(np.ndarray):
def __new__(cls, inputarr):
obj = np.asarray(inputarr).view(cls)
return obj
def remove_some(self, col, val):
return self[self[col] != val]
z = np.array([(1,2,3), (4,5,6), (7,8,9)],
dtype=[('a', int), ('b', int), ('c', int)])
d = Data(z)
d = d.remove_some('a', 4)
print(d)
The key difference here is that remove_some
does not try to modify self
, it merely returns a new instance of Data
.
I tried to do the same, but it is really very complex to subclass ndarray.
If you only have to add some functionality, I would suggest to create a class which stores the array as attribute.
class Data(object):
def __init__(self, array):
self.array = array
def remove_some(self, t):
//operate on self.array
pass
d = Data(z)
print(d.array)
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