.Need help guys, I have created a php page named picture.php. In this page I am retrieving a certain image from the database where I used the following codes to display the retrieved image:
header("Content-Type: image/jpeg");
imagejpeg($img);
imagedestroy($img);
.next, I want to 开发者_运维技巧use this page to serve as the source for an image to be displayed in an iframe using the following code:
<a id="various3" href="picture.php" title="<?php echo $info; ?>"><img class="last" src="./images/page11.jpg" /></a>
.various 3 is a jquery class where when i click the tag various 3 will pop-up an Iframe with picture.php inside it. and what i want to do is to set the size of the Iframe based on what is the size of the image from picture.php. help me with this please!
Here is tutorial for you to start from--> Here
You will have to store the resulting values within an array, or two separate variables.
In you iframe, this should work:
<?php
$valueWidth=500;
$valueHeight=250;
?>
<iframe src="" width="<?= $valueWidth ?>" height="<?= $valueHeight ?>"
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