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Creating an instance of a php key-value pair without an array

开发者 https://www.devze.com 2022-12-12 17:07 出处:网络
I\'m writing a recursive function to construct a multidimensional array. Basically, the problem is as follows:

I'm writing a recursive function to construct a multidimensional array. Basically, the problem is as follows:

function build($term){      
    $children = array();

    foreach ( $term->children() as $child ) {
        $children[] = build($child);
    }

    if(!count($children)){
        return $term->text();
    } else {
        return $term->t开发者_如何学运维ext() => $children; //obviously, this doesn't work           
    }
}

Thoughts? I know I could rewrite the structure of the function to make it work, but it seems like that should be unnecessary.


function build($term){          
    $children = array();

    foreach ( $term->children() as $child ) {
        $children += build($child);
    }

    if(!count($children)){
        return $term->text();
    } else {
        return array($term->text() => $children); //obviously, this doesn't work               
    }
}

From what i understand of the question this is what it should look like.

Appending the recursion and returning an array.

Edit: as an aside you might be better off returning an array even if count($children) ==0, this would get all of your types inline. else you may get all sorts of errors down the line:

if(!count($children)){
            return array($term->text() => null);


An array is the only key-value pair container PHP has to offer. So you HAVE to use an array if you want your function (may it be recursive or not) to return a key-value pair.

return array($term->text() => $children);


You could return it like this:

return array($term->text() => $children);

Although it's not what you asked. I think you cannot do this without rewriting parts of your function, one way or another.

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