Suggest me on how to change the following code into c++ code:
ROOTPROC VarUse
PROC VarUse
ROOT Cfile;
1 {
2 [
3 (?NameRef
4 (IF (AND (HAS-TYPE $parent Assignment) (IS-EQUAL $slot ``lhs开发者_运维知识库''))
5 (THEN (PRINT stdout "Variable %s defined at %s" $token $location))
6 (ELSE (PRINT stdout "Name %s accessed at %s" $token $location))))]
7 }
Apparently this code is "Algol 68 Genie". This code is not complete, but on the face of it must be equal next c++ code:
if(parent->hasType('Assigment') and slot == lhs)
{
std::cout << "Variable " << token << " defined at " << location << std::endl;
}
else
{
std::cout << "Name " << token << " accessed at " << location << std::endl;
}
Expressions like HAS-TYPE not have direct analogue. More about this language is written in the Algol 68 Genie
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