How to use SAX parse xml with the same tag and multi-attribute

When I use SAX to parse this XML,I don't know how to get this three "link" tag's href attribute开发者_JAVA技巧s value by the three different "rel" attributes.

<entry>
<title>ahbei</title>
<link href="http://api.douban.com/people/1000001" rel="self" />
<link href="http://www.douban.com/people/ahbei/" rel="alternate" />
<link href="http://img3.douban.com/icon/u1000001-20.jpg" rel="icon" />
<uri>http://api.douban.com/people/1000001</uri>
</entry>

I can't get the "http://img3.douban.com/icon/u1000001-20.jpg" by this code.

public void startElement(String uri, String localName, String qName,
            Attributes atts) throws SAXException {

        if (localName.equals("link") && (atts.getValue("rel") == "icon"))  // (*)
        {
            NowState = DBU_icon_url;
            DouBanUser.setIcon(atts.getValue(0));   
            return;
        }

    }

Thank you.

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change "if (localName.equals("link") && (atts.getValue("rel") == "icon"))" => "if (localName.equals("link") && atts.getValue("rel").equals("icon"))"

---

I think this will solve your problem.

NodeList link = elementW.getElementsByTagName("link");
int getLinkCount = link.getLength();
Element elementLink;
if (getLinkCount != 0) {
 for (int i = 0; i < getLinkCount; i++) {
     elementLink = (Element) Link.item(i);

   // Here you can get these three links.
}
}