Figuring out obscure pointer typedef

typedef solution_type (*algorithm_ptr_type) (
    problem_type problem,
    void (*post_evalua开发者_如何学JAVAtion_callback)(void *move, int score)/* = NULL*/
);

Please help me! Thank you

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This means, algorithm_ptr_type is a pointer to a function returning solution_type and whose parameters are:

• problem of type problem_type
• post_evaluation_callback which is again a function pointer taking two parameters (void* and int) , and returning void.

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And the same can be written as (easy and readable syntax):

typedef  void (*callback_type)(void *move, int score);

typedef solution_type (*algorithm_type)(problem_type, callback_type);

Note: the name of the parameters are optional, so I removed it, to make the typedef short and cute!

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In C++11, this can be simplified further as follows:

using algorithm_ptr_type = solution_type (*) (
    problem_type, 
    void(*)(void*, int)
);    

That is much better, as now it's clear as to what is being defined and in terms of what.

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In C++11, you can even define a utility to create function-pointer as,

//first define a utility to make function pointer.
template<typename Return, typename ... Parameters>
using make_fn = Return (*)(Paramaters...);

then use it as,

using callback_type = make_fn<void, void*, int>;

using algorithm_type = make_fn<solution_type, problem_type, callback_type>;

Here the first argument to make_fn is the return type, and the rest are the parameters — easy to decipher each one!

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Usage:

solution_type SomeFunction(problem_type problem, callback post_evaluation)
{
   //implementation

   //call the callback function
   post_evaluation(arg1, arg2);
   //..
}

algorithm_ptr_type function = SomeFunction;

//call the function
function(arg, someOtherFunction);

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what a horrible piece of code!

what its doing is defining a function pointer type called algorithm_ptr_type, returning a solution_type and taking a problem_type as its first arg and a callback as its second arg. the callback takes void* and int as its args and returns nothing.

a better way to write this would be:

typedef void (*post_evaluation_callback)(void *move, int  score);
typedef solution_type (*algorithm_ptr_type)(problem_type problem, post_evaluation_callback callback);

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This frustrating piece of code makes it so that algorithm_ptr_type is a function pointer.

This type must point to a function that returns an object of type solution_type.
This type must point to a function that takes the following arguments:
0: An object of type problem_type.
1: A function pointer which must point to a function that: Returns void.
Takes the following arguments:
0: A void*.
1: An int.

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Defines solution_type as a function pointer to a function that takes a problem_type and another function pointer. This second function pointer takes a void* (anything) and an int as parameters.