开发者

How to debug a program that is terminating in an unhandled exception?

开发者 https://www.devze.com 2022-12-12 14:32 出处:网络
I am programming in C++ on Linux platform. My program terminates with this (unhandled???) exception: \"terminate called after throwing an instance of \'long\'\"

I am programming in C++ on Linux platform.

My program terminates with this (unhandled???) exception:

"terminate called after throwing an instance of 'long'" Aborted

The code that is throwing the exception is inside try-catch block, then why should this happen?? The exception is thrown while returning from a function.

I am used to C programming and have very little experience in C++ (which is the main problem). I don't know how to debug this issue. I don't expect开发者_StackOverflow社区 a solution but a direction/pointer for debugging this problem.

Thanks in advance.


You can run your application under gdb (having built it with debug info using -g) and get it to break when an exception is thrown using the command:

(gdb) catch throw

This will take you to the origin of the exception. Some more info is available in this question:

  • Run an application in GDB until an exception occurs

Note that it is somewhat unusual to throw an ordinal type (such as a long). It may be in some temporary code, so grepping around might find it quickly enough.


It there anywhere on the call-stack with a exception specification or here? If there is then you might have this problem - you probably want to remove all of them.

If you are using gcc, then you can add this code first thing in main():

#ifdef __GNUC__
    std::set_terminate(__gnu_cxx::__verbose_terminate_handler);
#endif // ifdef __GNUC__

(More details at http://gcc.gnu.org/onlinedocs/libstdc++/manual/bk01pt02ch06s02.html)
Which will give you a better traceback from such exceptions.


you are probably catching the wrong exception type

use

catch(long)

or

catch(...)


Normally, I would recommend to set a breakpoint in the constructor of the thrown type -- but in this case ... I must admit to never have experienced that somebody has thrown a long like

throw 42;

That seems to me strange. Some debuggers might be able to catch an exception when it is thrown.

Is the called function yours?


Use set_terminate to break GDB

Example for set_terminate() is here

When it trigged - use bt command in GDB to see backtrace

0

精彩评论

暂无评论...
验证码 换一张
取 消

关注公众号