I got multiple checkboxes generated from a PHP script.
<input type="checkbox" class="checkbox" name="item[]" value="1" />
<input type="checkbox" class="checkbox" name="item[]" value="2" />
<input type="checkb开发者_StackOverflowox" class="checkbox" name="item[]" value="3" />
<input type="checkbox" class="checkbox" name="item[]" value="4" />
Now, once a checkbox gets checked - I want to show a div with options like "Delete Selected". But, after all checkboxes are unchecked, the DIV should disappear again. I have got the following code, but it does not hide the DIV.
$(".checkbox").live('click', function () {
countChecked () ;
if (countChecked() == "1" ) {
$("div#options").fadeOut("medium") ;
} else {
if ( $("div#options").is(":hidden") ) {
$("div#options").fadeIn ( "medium" ) ;
}
}
});
Also, the "countChecked"-function is shown below.
function countChecked() {
var n = $("input.checkbox:checked").length;
}
Your function should return the value:
function countChecked() {
return $("input.checkbox:checked").length;
}
And you want to check if the amount is 0, also you can remove the duplicate call to countChecked
$(".checkbox").live('click', function () {
if (countChecked() == 0 ) {
in your countChecked()
-function, use return statement..
function countChecked() {
var n = $("input.checkbox:checked").length;
return n;
}
and while clicking on checkboxes...
$(".checkbox").live('click', function () {
if (countChecked() == 0 ) {
$("div#options").fadeOut("medium") ;
} else {
if ( $("div#options").is(":hidden") ) {
$("div#options").fadeIn ( "medium" ) ;
}
}
});
You can use
$('.checkbox').live('click',function(){
// if you just checked the current one, no need to check the rest
if (this.checked)
{
$('#options').fadeIn('medium');
}
else // if you just unchecked
{
if ( !$('.checkbox:checked').length ) // check the whole group
{
$('#options').fadeOut('medium');
}
}
});
demo at http://jsfiddle.net/gaby/wZWbS/
Working: http://jsfiddle.net/NkkJF/
Another version, with tiny optimalization: http://jsfiddle.net/Briganti/XNWEP/
Have fun :)
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