Python equivalent of Ruby blocks for Sinatra-style URL routing

Is there a way of recreating Sinatra's URL routing in Python? And are there any reasons why this might not be desirable?

From Sinatra:

get '/' do
    'Hello world!'
end

From Flask (using decorators for routing):

@app.route("/")
def hello():
    return "Hello World!"

Sinatra achieves this succinctness through Ruby blocks:

def get(path, opts={}, &block)
    conditions = @conditions.dup
    route('GET', path, opts, &block)

    @conditions = conditions
    route('HEAD', path,开发者_如何学JAVA opts, &block)
end

I gather that Python does not have an exact equivalent of Ruby blocks, but that there are ways of recreating the functionality. How might this be done?

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As you said, Python doesn't have something like ruby blocks. Decorators are the commonly used solution for routing. The other way would be creating a list/dict containing the routes but since you seem to want the route definitions next to the underlying code, the decorator way is what you'll want to use.

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Another way would be using metaclasses, as it is done in webpy's web.autoapplication, source code for that.

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So, to your second question of 'And are there any reasons why this might not be desirable?'.

• Having named functions makes it possible to do things url_for(some_function), which makes it easy to restructure the site.
• named functions allow for testing, docstrings, etc.