I'm working on a flexible jCarousel that needs a number to know how many items it will scroll. But because the carousel is fluid/liquid width, the number is flexible too.
I guess I could do two t开发者_Python百科hings:
Count items: Is it possible to count items that are visible? There is a lot of items, but i want the number of items that is visible.
Calculate: I guess I could get the width and devide it by the width of the items. div.width() / 75 .. and make it return a single number. But how do I get the width of a DIV (let's say 1421px) and devide it by 75 (which is the width of a item) (which will be: 18,94666666666667) but will return the nearest number??
What and how should I do it? Thank you in advance...
I don't know, if there's an easy way to only get the visible items. If I understand that right, you mean the items in the visible area - otherwise you could use $('.item:visible')
, .item
being the class name of the carousel items.
For calculating try this:
var carouselWidth = $('#carousel').width(); // carousel main div with id=carousel
var numberOfItems = Math.round(carouselWidth / 75);
Hope this helps!
not sure about what you're trying to achieve here, but as for your 2 presented solutions:
counting visible items in jquery is possible via the ':visible' selector, but i guess this won't work for you as the jCarousel doesn't actually hide items via the css 'display' property, but instead covers them using the parent element as a mask.
calculation as you suggested might be the best option, from what i can see you just need to make use of the javascript's built-in Math functions, eg.
Math.floor(18.946)
will return18
Try carouFredSel: http://caroufredsel.frebsite.nl
It'll do all the calculations for you, even if your items have variable sizes...
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