I have created with the "extra" clause a concatenated field out of three text fields in a model - and I expect to be able to do this: q.filter(concatenated__icontains="y") but it gives me an error. What alternatives are there?
>>> q = Patient.objects.extra(select={'concatenated': "mrn||' '||first_name||' '||last_name"})
>>> q.filter(concatenated__icontains="y")
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "/usr/lib/python2.7/site-packages/django/db/models/query.py", line 561, in filter
return self._filter_or_exclude(False, *args, **kwargs)
File "/usr/lib/python2.7/site-packages/django/db/models/query.py", line 579, in _filter_or_exclude
clone.query.add_q(Q(*args, **kwargs))
File "/usr/lib/python2.7/site-packages/django/db/models/sql/query.py", line 1170, in add_q
can_reuse=used_aliases, force_having=force_having)
File "/usr/lib/python2.7/site-packages/django/db/models/sql/query.py", line 1058, in add_filter
negate=negate, process_extras=process_extras)
File "/usr/lib/python2.7/site-packages/django/db/models/sql/query.py", line 1237, in setup_joins
"Choices are: %s" % (name, ", ".join(names)))
FieldError: Cannot resolve keyword 'concatenated' into field. Choices are: first开发者_StackOverflow中文版_name, id, last_name, mrn, specimen
If you need something beyond this,
Patient.objects.filter(first_name__icointains='y' | last_name__icontains='y' | mrn__icontains='y')
you might have to resort to raw SQL.
Of course, you can add in your extra
either before or after the filter above.
My final solution based on Prasad's answer:
from django.db.models import Q
searchterm='y'
Patient.objects.filter(Q(mrn__icontains=searchterm) | Q(first_name__icontains=searchterm) | Q(last_name__icontains=searchterm))
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