When I try to upload file in Wicket I've got the following exception:
"ERROR org.apache.wicket.RequestCycle.logRuntimeException(RequestCycle.java:1529) - ServletRequest does not contain multipart content. One possible solution is to explicitly call Form.setMultipart(true), Wicket tries its best to auto-detect multipart forms but there are certain situation where it cannot.
java.lang.IllegalStateException: ServletRequest does not contain multipart content. One possible solution is to explicitly call Form.setMultipart(true), Wicket tries its best to auto-detect multipart forms but there are certain situation where it cannot.
at org.apache.wicket.protocol.http.servlet.MultipartSer开发者_如何学GovletWebRequest.<init>(MultipartServletWebRequest.java:113)..."
However, when I set form.MultiPart(true)
I can't get Javascript dialog by using:
target.appendJavascript("Some Message");
Does somebody know how to use Javascript when Form.Multipart(true)
?
Thanks!
If you want to call the alert dialog as a response for an ajax request, you can use the appendJavascript()
method (the argument is javascript code, not a simple string, like the code you posted):
target.appendJavaScript("alert('Some message');");
If you want to call the alert when the page loads, you could use a behavior:
add(new AbstractBehavior() { // or Behavior, on Wicket 1.5
@Override
public void renderHead(Component component, IHeaderResponse response) {
response.renderOnLoadJavaScript("alert('Some message');");
}
});
It's also possible use a Label, and render directly to a <script> tag. Just remember to call setEscapeModelStrings(false)
:
add(new Label("alert", "alert('Some message');").setEscapeModelStrings(false));
and
<script type="text/javascript" wicket:id="alert"></script>
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