This is the requirement
I am having my field declared in my class file as Datetime.
I am taking a string and i wou开发者_如何学Gold like to convert it to Datetime as my filed in my class is in date time
I always pass it as
String date="9999-12-31 00:00:00"
I would like to convert this to date time so that the output format should be the same as the given string
Quite simply, you're trying to parse "9999-12-31" with a format string of "yyyy-MM-ddTHH:mm:ss" - which it doesn't comply to, as it has no time.
EDIT: Okay, so you've now changed the input to "9999-12-31 21:34 PM" which still isn't in the appropriate format - there's no T, no seconds, and there's an am/pm designator. Why are you not using a format string which actually matches your input?
But if "9999-12-31" is the input, what output are you expecting?
Just change
DateTime dt = DateTime.ParseExact(strDate, "yyyy-MM-ddTHH:mm:ss", DateTimeFormatInfo.InvariantInfo, DateTimeStyles.None);
to
DateTime dt = DateTime.Parse(strDate, DateTimeFormatInfo.InvariantInfo, DateTimeStyles.None);
This will convert 9999-12-31 21:34 PM
to 9999-12-31
(if using dt.ToString("yyy-MM-dd")
).
Note that this DateTime will contain the hours/minutes etc. If you want to remove the hours/minutes from the DateTime, use something like this:
dt = new DateTime(dt.Year, dt.Month, dt.Day, 0, 0, 0, dt.Kind);
If you specify an format to DateTime.ParseExact, then your input string has to have exactly this format to be convertet to a DateTime. You can use DateTime.Parse instead.
DateTime dt = DateTime.Parse(strDate, DateTimeFormatInfo.InvariantInfo, DateTimeStyles.None);
DateTime.ParseExact(
strDate,
"yyyy-MM-dd hh:mm tt",
DateTimeFormatInfo.InvariantInfo,
DateTimeStyles.None);
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