I have a URLHandler that launches some application, the main code is as follows.
@implementation URLHandlerCommand
- (id)performDefaultImplementation {
NSString *urlString = [self directParameter];
NSLog(@"url :=: %@", urlString);
NSTask *task;
task = [[NSTask alloc] init];
[task setLaunchPath: @"/usr/bin/open"];
NSArray *arguments;
arguments = [NSArray arrayWithObjects: @"-a", @"Path Finder.app", urlString, nil];
[task setArguments: arguments];
NSPipe *pipe;
pipe = [NSPipe pipe];
[task setStandardOutput: pipe];
NSFileHandle *file;
file = [pipe fileHandleForReading];
[task launch];
return nil;
}
As the goal of this routine is to launch another application, I'd like to make this 开发者_开发百科URLHandler quit after launching an App. How can I do that?
You don't have to launch
open
usingNSTask
...open
just calls into Launch Services, some of whose functionality is directly available from NSWorkspace.To quit, you just call
[[NSApplication sharedApplication] terminate:nil]
. SeeNSApplication
documentation.
This has been answered here: Proper way to exit iPhone application? however you should also take a look at August's answer. Although it's not the accepted answer, it has been voted higher and it also follows Apple's set standards since Apple advises against force quitting iPhone applications.
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