I've been so out of touch with using PHP outside of content management systems that I've forgot some of the basic syntax etc. What I'm trying to build is a simple form that collects some user data and sends it to a database table called 'creathive_applications'.
Here is my HTML form:
<form action="<?php bloginfo('home'); ?>" method="post">
<fieldset id="membershipform">
<ul class="clearfix">
<li id="li-status">
<span>I am a:</span>
<menu>
<li><label for="student"><input disabled="disabled" type="radio" name="status" id="student" checked="checked" value="Graduate" /> Graduate</label></li>
<li><label for="student2"><input disabled="disabled" type="radio" name="status" id="student2" value="Undergraduate" /> Undergraduate</label></li>
</menu>
</li>
<li id="li-firstname">
<label for="firstname">First Name</label> <input name="firstname" disabled="disabled" type="text" placeholder="First Name" id="firstname" title="First Name" />
</li>
<li id="li-lastname">
<label for="lastname">Last Name</label> <input name="lastname" disabled="disabled" type="text" placeholder="Last Name" id="lastname" title="Last Name" />
</li>
<li id="li-email">
<label for="email">Email address</label> <input name="email" disabled="disabled" type="text" placeholder="Email address" id="email" title="Email address" />
</li>
<li id="li-url">
<label for="url">URL</label> <input name="url" disabled="disabled" type="text" placeholder="URL of something you've made" id="url" title="URL of something you've made" />
</li>
<li id="li-buttons">
<input name="submit" type="submit" value="Send Application ►" title="Send Application" onclick="alert('Invites available from March 2011');" />
</li>
</ui>
</fieldset>
</form>
and here is the PHP jazz:
if(isset($_POST['submit']))
{
$status = $_POST['status'];
$firstname = $_POST['firstname'];
$lastname = $_POST['lastname'];
$email = $_POST['email'];
$url = $_POST['url'];
$host = '####';
开发者_StackOverflow社区$username = '####';
$pass = '####';
mysql_connect($host,$username,$pass);
mysql_select_db($username);
$query = "INSERT INTO creathive_applications VALUES (NULL,'".$status."','".$firstname."','".$lastname."','".$email."','".$url."')";
$result = mysql_query($query);
}
Can anyone help me fix this as I can't remember how to run my SQL statement and send the data to the database :/ Also I've added the database username and password as well as host but what about the database name? Where does that go again?
I know this is a rather n00b question, but any help would be much appreciated.
THANKS A LOT
Well, with no error it's impossible to tell what to fix.
However, there are some obvious things to do.
See the comments:
<?
//show all possible errors. should be ALWAYS set to that level
error_reporting(E_ALL);
echo "landed at form handler<br>";
// sometimes buttons not being sent or gets misspelled
if($_SERVER['REQUEST_METHOD'] == 'POST')
{
echo "here goes POST processing<br>";
$host = '####';
$username = '####';
$pass = '####';
mysql_connect($host,$username,$pass);
mysql_select_db($username);
// all strings should be escaped
// and it should be done after connecting to DB
$status = mysql_real_escape_string($_POST['status']);
$firstname = mysql_real_escape_string($_POST['firstname']);
$lastname = mysql_real_escape_string($_POST['lastname']);
$email = mysql_real_escape_string($_POST['email']);
$url = mysql_real_escape_string($_POST['url']);
$query = "INSERT INTO creathive_applications
VALUES (NULL,'$status','$firstname','$lastname','$email','$url')";
echo $query;
// always run your queries this way to be notified in case of error
$result = mysql_query($query) or trigger_error(mysql_error().". Query: ".$query);
var_dump($result);
}
in case you still see no error, add this line temporarily to the top of the script
ini_set('display_errors',1);
and remove it immediately after you get the problem solved.
EDIT
added some debug info.
If you see none of it's messages, you're sending your form to the wrong URL.
If you see some of them, post it here
As Brian noted, you should post if any errors are happening.
The main thing I notice is that you are using variables that potentially have no values. Radio buttons do not send their values if they are not toggled.
Use something like this to cover your bases:
if(isset($_POST['status']))
{
$status = $_POST['status'];
}
Don't know if that's your problem. Consider adding more information. :)
if(count($_POST) > 0){
$status = $_POST['status'];
$firstname = $_POST['firstname'];
$lastname = $_POST['lastname'];
$email = $_POST['email'];
$url = $_POST['url'];
$host = '####';
$username = '####';
$pass = '####';
$mydb = mysql_connect($host,$username,$pass);
// mysql_select_db($username);
//are you using your username as db name?
mysql_select_db("yourdbname");
$query = "INSERT INTO creathive_applications VALUES (NULL,'".mysql_real_escape_string($status)."','".mysql_real_escape_string($firstname)."','".mysql_real_escape_string($lastname)."','".mysql_real_escape_string($email)."','".mysql_real_escape_string($url)."')"; //use mysql_real_escape_string for security
$result = mysql_query($query);
//show error if query fails.
if (!$result) {
die('Invalid query: ' . mysql_error());
}
mysql_close($mydb); //close the connection
}
add the mysql_error();
and see if it prints out errors
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