If I have a table with two columns, A and B, and would like to count how many times an item shows up in both columns, is there a way to do so without using a cursor or temp table?
Ex:
Column A Column B
BMW Ford
Jaguar BMW
Mercedes Lexus
Chevrolet Jaguar
BMW Ford
I would like the result to be:
BMW 3
Jaguar 2
Mercedes 1
Chevrolet 1
Ford 2
Lex开发者_Python百科us 1
SELECT ColumnA, COUNT(*) as Times
FROM (
SELECT ColumnA FROM ATable
UNION ALL
SELECT ColumnB FROM ATable) Joined
GROUP BY ColumnA
Most DBMS require you to alias the derived table
SELECT x, COUNT(*)
FROM (SELECT ColumnA AS x FROM t
UNION ALL
SELECT ColumnB FROM t)
GROUP BY x
You don't say DBMS. If SQL Server you can use UNPIVOT
to avoid scanning the table twice.
SELECT car, COUNT(*)
FROM YourTable
UNPIVOT (car FOR col in (ColumnA, ColumnB)) u
GROUP BY car
Depending on what indexes you have this could be either more or less efficient than the UNION ALL
approach (If both ColumnA
and ColumnB
were indexed the UNION ALL
query plan could do a merge join on the 2 indexes and feed that into the aggregation operator avoiding the need to sort the data that the UNPIVOT
plan would require)
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