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Help resolving SQL error that occurs in code but not in SQL workbench

开发者 https://www.devze.com 2023-02-11 12:54 出处:网络
I run this command in SQL Workbench and it returns my desired results, but it return a syntax error in the browser...

I run this command in SQL Workbench and it returns my desired results, but it return a syntax error in the browser...

$sql = "SELECT
        SUBSTRING(`last_name`, 1, 1) AS alpha,
        SUBSTRING(`middle_name`, 1, 1) AS subMiddleName,
        `idClients`,
        `type`,开发者_高级运维
        `first_name`,
        `middle_name`,
        `last_name`,
        `address`,
        `primary_number`,
        `secondary_number`,
        `home_number`,
        `office_number`,
        `cell_number`,
        `fax_number`,
        `ext_number`,
        `other_number`,
        `comments`
    FROM `clients`
    WHERE `user_id` = 2
    AND `is_sub` = 0
    AND `prospect` = 1
    ORDER BY `last_name`";

Also user_id, is_sub, and prospect are of the INT data type if anyone wants to know. I tried to treat them as strings in the query, but that still didn't help.

this is the error i get

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'AND prospect = 1 AND type = 'Buyer'' at line 1


You're not showing us the same query, or the relevant PHP code, as nowhere does the above query use the string 'Buyer'.

That said, you may need to escape the column name type with backticks:

AND `prospect` = 1 AND `type` = 'Buyer'
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